i think this is a really clean explanation of why (-3) * (-3) should equal 9. i wanted to point out that with a little more work, it’s possible to see why (-3) * (-3) must equal 9. and this is basically a consequence of the distributive law:
the first equality uses 0 * anything = 0. the second equality uses (3 + -3) = 0. the third equality uses the distribute law, and the fourth equality uses 3 * (-3) = -9, which was shown in the previous comment.
so, by adding 9 to both sides, we get:
9 = 9 - 9 + (-3) * (-3).
in other words, 9 = (-3) * (-3). this basically says that if we want the distribute law to be true, then we need to have (-3) * (-3) = 9.
it’s also worth mentioning that this is a specific instance of a proof that shows (-a) * (-b) = a * b is true for arbitrary rings. (a ring is basically a fancy name for a structure with addition and distribute multiplication.) so, any time you want to have any kind of multiplication that satisfies the distribute law, you need (-a) * (-b) = a * b.
in particular, (-A) * (-B) = A * B is also true when A and B are matrices. and you can prove this using the same argument that was used above.
You can look at multiplication as a shorthand for repeated addition, so, for example:
In other words we have three lots of three. The zero will be handy later…
Next consider:
Here we have three lots of minus three. So what happens if we instead have minus three lots of three? Instead of adding the threes, we subtract them:
Finally, what if we want minus three lots of minus three? Subtracting a negative number is the equivalent of adding the positive value:
Do let me know if some of that isn’t clear.
This was very clear. Now that I see it, I realize it’s the same reasoning why x^(-3) is 1/(x^3):
2 × -3 = -6 1 × -3 = -3 0 × -3 = 0 -1 × -3 = 3Thank you!
i think this is a really clean explanation of why (-3) * (-3) should equal
9. i wanted to point out that with a little more work, it’s possible to see why (-3) * (-3) must equal 9. and this is basically a consequence of the distributive law:0 = 0 * (-3) = (3 + -3) * (-3) = 3 * (-3) + (-3) * (-3) = -9 + (-3) * (-3).the first equality uses
0 * anything = 0. the second equality uses(3 + -3) = 0. the third equality uses the distribute law, and the fourth equality uses3 * (-3) = -9, which was shown in the previous comment.so, by adding
9to both sides, we get:9 = 9 - 9 + (-3) * (-3).in other words,
9 = (-3) * (-3). this basically says that if we want the distribute law to be true, then we need to have (-3) * (-3) = 9.it’s also worth mentioning that this is a specific instance of a proof that shows
(-a) * (-b) = a * bis true for arbitrary rings. (a ring is basically a fancy name for a structure with addition and distribute multiplication.) so, any time you want to have any kind of multiplication that satisfies the distribute law, you need (-a) * (-b) = a * b.in particular,
(-A) * (-B) = A * Bis also true whenAandBare matrices. and you can prove this using the same argument that was used above.